Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - 2-1 Solving One-Step Equations - Practice and Problem-Solving Exercises - Page 86: 75

Answer

2450

Work Step by Step

To solve this find the number of letters that are e, which is 2800/8: $e=2800\div8=350$ Number of letters that aren't e: $x=2800-350=2450$
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