Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - Chapter Review - Page 790: 37

Answer

$\frac{1}{2}$

Work Step by Step

Use P(even)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$. There are 6 possible outcomes:1,2,3,4,5,6.There are 3 favorable outcomes:2,4 and 6. Plug in the number of outcomes: P(even)=$\frac{3}{6}$ -simplify- p(even)=$\frac{1}{2}$
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