Answer
6
Work Step by Step
Use the formula of permutation: $_{n}$P$_{y}$=$\frac{n!}{(n-r)!}$. Plug in 3 for N and 2 for R:
$_{n}$P$_{y}$=$\frac{n!}{(n-r)!}$
$_{3}$P$_{2}$=$\frac{3!}{(3-2)!}$ -simplify-
$_{3}$P$_{2}$=$\frac{3!}{1!}$ -write using factorial-
$_{3}$P$_{2}$=$\frac{3*2*1}{1}$ -simplify-
$_{3}$P$_{2}$=6
