Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 780: 20

$\frac{1}{18}$

The probabilities are independent. P(Blue 1 or 2): P(blue 1 or 2)=$\frac{1}{6}$+$\frac{1}{6}$=$\frac{2}{6}$ P(blue 1 or 2)=$\frac{1}{3}$ P(green 1): P(green 1)=$\frac{1}{6}$ P(blue 1 or 2 and green 1)=P(blue 1 or 2) $\times$ P(green 1) P(blue 1 or 2 and green 1)=$\frac{1}{3}$ $\times$ $\frac{1}{6}$ P(blue 1 or 2 and green 1)=$\frac{1}{18}$