Answer
10
Work Step by Step
We know that:
$_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$
$\frac{5!}{(5-3)!3!}$
$\frac{5*4*3*2*1}{3*2*1*2*1}$
10
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