Answer
Minimum=5
1st quartile=8
Median=10
3rd quartile=10.5
Maximum=12
Work Step by Step
You have the values :9,5,7,10,11,10,12.
-->Minimum is the smallest value in the data set which is 5.
-->Arrange the data from least to greatest(5,7,9,10,10,11,12) to find the middle number.The median is 10.
-->The maximum is the largest value in the set which is 12.
-->The first quartile is the middle value between the minimum and median:(5,7,9,10)The middle values are 7 and 9.Find the average by adding the two numbers and dividing by 2: (7+9)/2=8
-->The third quartile is the middle value between the median and the maximum(10,10,11,12). The middle values are 10 and 11. Find the average by adding the two numbers and dividing by 2: (10+11)/2=10.5
Minimum=5.1st quartile=8.Median=10.3rd quartile=10.5.Maximum=12
