Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-3 Measures of Central Tendency and Dispersion - Practice and Problem-Solving Exercises - Page 742: 19

Answer

The first player has a larger spread while the second player has a higher average

Work Step by Step

The first player has 0.265,0.281,0.294,0.316,0.318,0.327 The second player has 0.285,0.291,0.303,0.304,0.312,0.314. 1st Mean: Add all the numbers and divide them by 6: $\frac{0.265+0.281+0.294+0.316+0.318+0.327}{6}$=0.300 2nd mean: Add all the numbers and divide them by 6:$\frac{0.285+0.291+0.303+0.304+0.312+0.314}{6}$=0.302 The second player has a higher average. 1st range: Difference between the largest and smallest value: 0.327-0.265=0.062 2nd range: Difference between the largest and smallest value: 0.314-0.285=0.029 The first player has a higher spread. The first player has a larger spread while the second player has a higher average.
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