Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Common Core Cumulative Standards Review - Selected Response - Page 721: 4

Answer

H.

Work Step by Step

We will need to factor the numerator to find the equivalent expression. $\frac{18x^2y+24x^3y^4-12x^7y^2}{6x^2y}$ $=\frac{6x^2y\times3+6x^2y\times4xy^3-6x^2y\times2x^5y}{6x^2y}$ $=\frac{6x^2y(3+4xy^3-2x^5y)}{6xy^2}$ $=3+4xy^3-2x^5y$ (choose H).
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