Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Chapter Review - Page 717: 20

Answer

$\frac{-15x^2+23x+27}{(3x-1)(2x+3)}$

Work Step by Step

$\frac{9}{3x-1}-\frac{5x}{2x+3}$ $=\frac{9(2x+3)}{(3x-1)(2x+3)}-\frac{5x(3x-1)}{(3x-1)(2x+3)}$ $=\frac{18x+27}{(3x-1)(2x+3)}-\frac{15x^2-5x}{(3x-1)(2x+3)}$ $=\frac{18x+27-15x^2+5x}{(3x-1)(2x+3)}$ $=\frac{-15x^2+23x+27}{(3x-1)(2x+3)}$
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