Answer
The answer is $2m+3$.
Work Step by Step
Given: $(2m^2-m-3) \div (m+1)$
Begin the long division process:
Divide: $2m^2 \div m =2m$
Multiply: $2m^2 +2m$
Then subtract: $-3m -3$
Repeat the process:
Divide: $-3m \div m = -3$
Multiply: $-3(m+1)=-3m-3$
Then subtract. The remainder is $0$.
The answer is $2m+3$.
