Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Got It? - Page 673: 6

Answer

$\frac{1}{q^2}$.

Work Step by Step

The given expression is $=\frac{\frac{1}{q+4}}{\frac{2q^2}{2q+8}}$ Write as a quotient. $=\frac{1}{q+4}\div \frac{2q^2}{2q+8}$ $=\frac{1}{q+4}\times \frac{2q+8}{2q^2}$ Factor. $=\frac{1}{q+4}\times \frac{2(q+4)}{2q^2}$ Divide out the common factors. $= \frac{1}{q^2}$.
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