Answer
a. $(x-7)(3x-2)$.
b. $(x+1)(x+3)$.
Work Step by Step
a.
The given expression is
$=\frac{2x-14}{4x-6}\cdot \left (6x^2-13x+6 \right )$
Factor.
$=\frac{2(x-7)}{2(2x-3)}\cdot (2x-3)(3x-2)$
Divide out the common factors $2$ and $2x-3$.
$=(x-7)(3x-2)$.
b.
The given expression is
$=\frac{x^2+2x+1}{x^2-1}\cdot \left (x^2+2x-3 \right )$
Factor.
$=\frac{(x+1)(x+1)}{(x-1)(x+1)}\cdot (x-1)(x+3)$
Divide out the common factors $x+1$ and $x-1$.
$= (x+1)(x+3)$.
