Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Common Core Cumulative Standards Review - Selected Response - Page 659: 11

Answer

$(A) r=\frac{\sqrt{A\pi}}{\pi} $.

Work Step by Step

Area of the circle: $\Rightarrow A=\pi r^2$ Divide both sides by $\pi$. $\Rightarrow \frac{A}{\pi}=\frac{\pi r^2}{\pi}$ Simplify. $\Rightarrow \frac{A}{\pi}= r^2$ Divide and multiply the left hand side by $\pi$: $\Rightarrow \frac{A\pi}{\pi^2}= r^2$ Take the square root of both sides: $\Rightarrow \sqrt{\frac{A\pi}{\pi^2}}= \sqrt{r^2}$ Simplify. $\Rightarrow \frac{\sqrt{A\pi}}{\pi}=r$ Hence, the correct option is $(A) r=\frac{\sqrt{A\pi}}{\pi} $.
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