Answer
s=-2
Work Step by Step
You are given $\sqrt (s+10)$=$\sqrt (6-s)$.Solve for S:
$\sqrt (s+10)$=$\sqrt (6-s)$ -square both sides-
($\sqrt (s+10$$)^{2}$=($\sqrt (6-s$$)^{2}$
s+10=6-s
2s+10=6
2s=-4
s=-2
The final solution is s=-2
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 22
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