Answer
$x=7$
Work Step by Step
$\sqrt 7x-4=\sqrt 5x+10$
$(\sqrt 7x-4)^2=(\sqrt 5x+10)^2$
$7x-4=5x+10$
$2x=14$
$x=7$
Check:
$\sqrt 7x-4=\sqrt 5x+10$
$\sqrt 7(7)-4=\sqrt 5(7)+10$
$3\sqrt 5=3\sqrt 5$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Got It? - Page 634: 3
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