Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 630: 51

Answer

$=\frac{13+\sqrt 65+\sqrt 130+5\sqrt 2}{8}$

Work Step by Step

$\frac{\sqrt 13+\sqrt 10}{\sqrt 13-\sqrt 5}$ Multiply the equation with $\frac{\sqrt 13+\sqrt 5}{\sqrt 13+\sqrt 5}$ $=\frac{(\sqrt 13+\sqrt 10)(\sqrt 13+\sqrt 5)}{13-5}$ $=\frac{13+\sqrt 65+\sqrt 130+\sqrt 50}{8}$ $=\frac{13+\sqrt 65+\sqrt 130+5\sqrt 2}{8}$
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