Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Got It? - Page 628: 4

Answer

$\frac{-3\sqrt{10}+3\sqrt{5}}{5}$.

Work Step by Step

The given expression is $=\frac{-3}{\sqrt{10}+\sqrt{5}}$ Multiply the numerator and denominator by the conjugate of the denominator. $=\frac{-3}{\sqrt{10}+\sqrt{5}}\cdot \frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}-\sqrt{5}}$ Multiply in the denominator. $=\frac{-3(\sqrt{10}-\sqrt{5})}{10-5}$ Simplify the denominator. $=\frac{-3(\sqrt{10}-\sqrt{5})}{5}$ Clear the parentheses in the numerator. $=\frac{-3\sqrt{10}+3\sqrt{5}}{5}$.
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