Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Got It? - Page 622: 5

Answer

a. 4 b. $3\div a$ c. $5y\sqrt y \div z$

Work Step by Step

a. We can simplify as follows: = $\sqrt (144 \div 9)$ = $\sqrt 16$ = 4. b. We can simplify as follows: = $\sqrt (36a \div 4a^{3})$ = $\sqrt 36\sqrt a \div \sqrt 4\sqrt a^{3}$ = $6\sqrt a \div 2a\sqrt a$ = $3 \div a$. c. We can simplify as follows: = $\sqrt (25y^{3} \div z^{2})$ = $\sqrt 25\sqrt y^{2}*\sqrt y \div \sqrt z^{2}$ = $5y*\sqrt y \div z$ = $5y\sqrt y \div z$.
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