Answer
$\delta = 5.86$ mm
Work Step by Step
\lt$\delta = \frac{FL}{AE}=\sigma \frac{L}{E}=140(10^6)\frac{3}{71.7(10^9)}=0.00586$ m $= 5.86$ mm
Shigley's Mechanical Engineering Design 10th Edition
by Budynas, Richard; Nisbett, Keith
Published by
McGraw-Hill Education
ISBN 10:
0073398209
ISBN 13:
978-0-07339-820-4
Chapter 3 - Problems - Page 143: 3-27
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