Answer
$R_O=1.39$ kN
$R_A=1.6$ kN
Work Step by Step
$R_O = \frac{0.8}{\tan 30}=1.39$ kN
$R_A = \frac{0.8}{\sin 30}=1.60$ kN
Shigley's Mechanical Engineering Design 10th Edition
by Budynas, Richard; Nisbett, Keith
Published by
McGraw-Hill Education
ISBN 10:
0073398209
ISBN 13:
978-0-07339-820-4
Chapter 3 - Problems - Page 141: 3-3
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