Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 3 - Equilibrium of a Particle - Section 3.3 - Coplanar Force Systems - Problems - Page 104: 39

Answer

$2.42m$

Work Step by Step

We know that $\Sigma F_x=0$ $\implies -ABcos\theta+100=0$.....eq(1) and $\Sigma F_y=0$ $\implies ABsin\theta-20(9.8)=0$...eq(2) Dividing eq(2) by eq(1), we obtain: $tan\theta=\frac{196.2}{100}$ Solve for $\theta$ by using inverse tangent: $\theta=63$ Now $2tan\theta=d+1.5$ This simplifies to: $d=2.42m$
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