Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 3 - Equilibrium of a Particle - Section 3.3 - Coplanar Force Systems - Problems - Page 101: 22

Answer

$158N$

Work Step by Step

We can find the required force as $F_{spring}=K\Delta x$ $\implies F_{spring}=500(3.354-3)=177N$ We know that $\Sigma F_x=0$ $\implies -F+2F_{spring} cos(63.4)=0$ $\implies -F+2(177N) cos(63.4)=0$ This simplifies to: $F=158N$
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