Answer
$v_B=4ft/s$
$v_C=6ft/s$
Work Step by Step
We can determine the required linear velocity as follows:
From the given diagram
$r_{IC/A}=\frac{8}{2}=4ft$
Now, $v_C=\omega r_{IC/C}$
We plug in the known values to obtain:
$v_C=2\times 3=6ft/s$
and $v_B=\omega{r_{IC/B}}$
We plug in the known values to obtain:
$v_B=2\times 2=4ft/s$
