Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 14 - Kinetics of a Particle: Work and Energy - Section 14.4 - Power and Efficiency - Problems - Page 212: 61

Answer

$P=400(10^3)tW$

Work Step by Step

The power generated can be determined as follows: $a=\frac{T}{m}$ $\implies a=\frac{20\times 10^3}{m}=20m/s^2$ According to the equations of kinematics $v=v_{\circ}+at$ $\implies v=0+20t$ $\implies v=20tm/s$ Now $P=F\cdot v=T\cdot v$ We plug in the known values to obtian: $P=(20\times 10^3)(20t)$ $\implies P=400(10^3)tW$
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