Answer
$P=12.6KW$
Work Step by Step
We can determine the required power as follows:
The height of the steps is given as
$H=nh=32(0.125)=4m$
The weight of the steps is
$W=nmg=32(150)(9.81)=47088N$
Now $v_y=vsin\theta=0.6(\frac{4}{\sqrt{(32(0.25)^2)+(4)^2}})=0.268m/s$
The power can be calculated as
$P=Fv$
$\implies P=Wv$
We plug in the known values to obtain:
$P=(47088)(0.0268)$
$\implies P=12.6KW$
