Answer
$N=7.36N$, $v=1.63m/s$
Work Step by Step
We can determine the required normal force and speed as follows:
$K_s=m\frac{mv^2}{\rho}$
We plug in the known values to obtain:
$200(0.1)=0.75\frac{v^2}{0.1}$
This simplifies to:
$v=1.63m/s$
As $\Sigma F_b=0$
$\implies N_b=mg=0.75\times 9.81=7.36N$
Now $N=\sqrt{N^2_b+N^2_t}$
We plug in the known values to obtain:
$N=\sqrt{(7.36)^2+(0)^2}$
$\implies N=7.36N$
