Answer
$R=19.0$ m
$t=2.48$ s
Work Step by Step
$s_B=s_A+v_At$
$R=0+10\cos 40 t$
$s_B=s_A+v_At+\frac{1}{2}a_ct^2$
$-R(\frac{3}{4})=0+10\sin 40t - \frac{1}{2}(9.81)t^2$
Solving
$R=19.0$ m
$t=2.48$ s
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.6 - Motion of a Projectile - Problems - Page 55: 106
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