Answer
$s=123$ ft
$a=2.99$ ft/s$^2$
Work Step by Step
$v=60(1-e^{-t})$
$\int_0^s ds = \int v dt = \int_0^3 60(1-e^{-t})dt$
$s=60(t+e^{-t})|^3_0$
$s=123$ ft
$a=\frac{dv}{dt}=60(e^{-t})$
At $t=3$ s
$a=60e^{-3}=2.99$ ft/s$^2$
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