Answer
Normal: $d=517$ ft
Drunk: $d = 616$ ft
Work Step by Step
Normal:
Distance moved before reacting: $d'=v_0t=44(0.75)=33$ ft
$v^2=v_0^2+2a_c(d-d')$
$0^2=44^2+2(-2)(d-33)$
$d=517$ ft
Drunk:
Distance moved before reacting: $d'=v_0t=44(3)=132$ ft
$v^2=v_0^2+2a_c(d-d')$
$0^2=44^2+2(-2)(d-132)$
$d=616$ ft