Answer
$\Delta s_B = 1.33$
Work Step by Step
$2s_B+(s_B-s_C)=l$
$3s_B-s_C=l$
$3\Delta s_B - \Delta s_C=0$
Since $\Delta s_C=-4$, then
$3 \Delta s_B = 04$
$\Delta s_B = -1.33$ ft
$\Delta s_B = 1.33$ ft (towards the right)
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.10 - Relative-Motion of Two Particles using Translating Axes - Problems - Page 98: 199
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