Answer
The total number of characters $(ch)$ is
$2$ surfaces/disk $\times 50$ tracks/surface $\times 20$ sectors /track $\times 1024$ ch/sector,
which is $2,048,000$ characters on a single disk.
Work Step by Step
The total number of characters $(ch)$ is
$2$ surfaces/disk $\times 50$ tracks/surface $\times 20$ sectors /track $\times 1024$ ch/sector,
which is $2,048,000$ characters on a single disk.