Answer
With a cache hit rate of 92$\%$ , the average access time is
$(0.92 \times 10)+0.08 \times(10+25)=12.0$ nsec
Work Step by Step
With a cache hit rate of 92$\%$ , the average access time is
$(0.92 \times 10)+0.08 \times(10+25)=12.0$ nsec
Invitation to Computer Science 8th Edition
by Gersting, Judith L.; Schneider, G. Michael
Published by
Cengage Learning
ISBN 10:
1337561916
ISBN 13:
978-1-33756-191-4
Chapter 5 - 5.2 - The Components of a Computer System - Practice Problems - Page 238: 6
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