Invitation to Computer Science 8th Edition

Published by Cengage Learning
ISBN 10: 1337561916
ISBN 13: 978-1-33756-191-4

Chapter 4 - Exercises - Page 217: 3b

Answer

110001 (base 2 / binary) = 49 (base 10 / decimal)

Work Step by Step

110001 (base 2) into base 10 (decimal): $$(1*2^{5}) + (1*2^{4}) + (0*2^{3}) + (0*2^{2}) + (0*2^{1}) + (1*2^{0})= 32 + 16 + 0 + 0 + 0 + 1 = 49 $$
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