Answer
a) isEqual = False
b) isEqual = True
c) b = False
d) b = False
e) x = 9 (Len also counts White space characters)
f) x = " " (Index 0 is white space character)
g) s3 = " Welcome welcome " (2 White space characters between s1,s2)
h) s3 = "Welcome " (0 index white space character is removed)
i) s3 = "Welc" (0 index white space character and only till 4 index is taken as 5 index is exclusive
j) s3 = " welcome "
k) s3 = " WELCOME "
l) s3 = "Welcome" (Removes White space characters in the beginning and ending)
m) s3 = " WElcomE " (Replaces all occurences of e with E)
n) x = 1 (It means e is present in s1 at index 1)
o) x = -1 (It means abc is not present in s1)
Work Step by Step
a) isEqual = (s1 == s2)
b) isEqual = (s1.lower() == s2.lower())
c) b = s1.startswith("AAA")
d) b = s1.endswith("AAA")
e) x = len(s1)
f) x = s1[0]
g) s3 = s1 + s2
h) s3 = s1[1:]
i) s3 = s1[1:5]
j) s3 = s1.lower()
k) s3 = s1.upper()
l) s3 = s1.strip()
m) s3 = s1.replace("e", "E")
n) x = s1.find("e")
o) x = s1.rfind("abc")
