Computer Science: An Overview: Global Edition (12th Edition)

Published by Pearson Higher Education
ISBN 10: 1292061162
ISBN 13: 978-1-29206-116-0

Chapter 4 - Networking and the Internet - Chapter Review Problems - Page 211: 14

Answer

a) 00000101 00010010 00100011 = 5.18.35.0 b) 10000000 00100000 = 128.32.0.0 c) 00110000 00011000 = 48.24.0.0

Work Step by Step

To convert to dotted decimal, split the binary number into groups of 8. Then simply convert each group into a decimal number using the base of 2. $2^{0}=1$, $2^{1}=2$, $2^{2}=4$, $2^{3}=8$, $2^{4}=16$, $2^{5}=32$, $2^{6}=64$, $2^{7}=128$ a) So 00000101 = 5, 00010010 = 18, 00100011 = 35 and fourth place is absent so its 0. Therefore, 00000101 00010010 00100011 = 5.18.35.0. b) So 10000000 = 128, 00100000 = 32, and third and fourth place is absent so its 0. Thus, 10000000 00100000 = 128.32.0.0 c) So 00110000 = 48 and 00011000 = 24 and third and fourth place is absent so its 0. Thus, 00110000 00011000 = 48.24.0.0
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.