Answer
$i= 16 - \frac{2}{5}I$
Work Step by Step
We find:
$(y-y_{1})=(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}) (x-x_{1})$
$(y-14)=(\frac{12-14}{10-5} (x-5)$
$y-14=\frac{-2}{5}(x-5)$
$5y-70=-2x + 10$
$5y+ 2x= 80$
$5y=80-2x$
$y=16-\frac{2x}{5}$
$i=16-\frac{2}{5}I$
