Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 40: 95

Answer

$$40mi/gal$$

Work Step by Step

1. Use the following conversion factors: $1 km = 0.62137 mi$ and $1 L = 0.26417Gallon$ 2. Multiply km value with conversion factor to miles, and liter with conversion factor to gallons. $$(17 km\times0.62137miles/km)\div(1L\times0.26417 gallons/L) = 39.98671 mi/gal \approx 40mi/gal$$
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