Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 70a

Answer

$22.44g$

Work Step by Step

$m=p\times V=0.7857 \frac{g}{cm^{3}} \times 28.56 cm^{3}=22.439592g \approx 2.44g$
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