Answer
No, the density of the penny is less than the pure copper.
Work Step by Step
$D=\frac{m}{v}$ density equation Density of the penny $D=\frac{2.49g}{0.349 cm^{3}}=7.13\frac{g}{cm^{3}}$,
$7.13\frac{g}{cm^{3}}$is less than density of the pure copper $8.93\frac{g}{cm^{3}}$