Answer
$1228g/L = 1228 \times 10^{-3} g/mL$ and $1228 \times 10^{-9} kg/ML$
Work Step by Step
1)$1228\frac{g}{L}\times \frac{L}{1000mL} = 1.228g/mL = 1228 \times 10^{-3} g/mL$
2) $1228\frac{g}{L} \times\frac{kg}{1000g} \frac{10^{6}L}{ML} = 1228 \times 10^{-9} kg/ML$
