Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 58d

Answer

$1.5 \times 10^{-2} g$

Work Step by Step

centi (c) =$10^{-2}$ $1.5 cg =1.5 \times 10^{-2} g$
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