Answer
a. 1120 g ethanol
b. 780 g mercury
Work Step by Step
a.
$\text{1.50 quart} \times \frac{\text{1 L}}{\text{1.0567 quart}}\times \frac{\text{1000 mL}}{\text{1 L}}\times \frac{\text{0.789 g}}{\text{1 mL}}$ = 1120 g ethanol
b.
$\text{3.5 in}^{2} \times \left(\frac{\text{2.54 cm}}{\text{1 in}}\right)^{3}\times \frac{\text{13.6 g}}{\text{1 cm}^{3}}$ = 780 g mercury
