Answer
Volume = 101.5 $cm^{3}$
Density = 6.059 $\frac{g}{cm^{3}}$ = 6059$\frac{kg}{m^{3}}$
Work Step by Step
Given:
Dimensions - 2.9 cm $\times$ 3.5 cm $\times$ 10 cm
Mass = 615.0 g
Volume of rectangular block = Length $\times$ breadth $\times$ height = 2.9 cm $\times$ 3.5 cm $\times$ 10 cm
$\therefore$ Volume = 101.5 $cm^{3}$
Since Density = $\frac{Mass}{Volume}$ = $\frac{615}{101.5}$
$\therefore$ Density = 6.059 $\frac{g}{cm^{3}}$
Since 1$\frac{g}{cm^{3}}$ = 1000$\frac{kg}{m^{3}}$
6.059 $\frac{g}{cm^{3}}$ = 6059$\frac{kg}{m^{3}}$
