Answer
The spherical ball will sink in water
Work Step by Step
Given:
radius: 0.50 cm
Volume of a sphere (4/3)πr³
V=(4/3)π(0.50)³= 0.5236 cm³ (only has two sig figs)
m= 2.0 g
D=m/v
D=2.0 g/0.5236 cm³
D=3.8 g/cm³ (two sig figs)
*remember 1 mL=1 cm³, so
D=3.8 g/mL
For the ball to float in water, it must have a density of less than 1.0 g/mL. The density of the ball is greater than 1.0, meaning that the ball will sink.
