Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 696: 51

Answer

$-\frac{4}{7}$

Work Step by Step

$(\frac{2}{3})(-\frac{6}{7})=-\frac{2\times6}{3\times7}=-\frac{12}{21}=-\frac{12\div3}{21\div3}=-\frac{4}{7}$
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