Answer
$\frac{21}{8}\leq x$
Work Step by Step
$\frac{x}{6}+\frac{1}{8}\leq\frac{x}{2}-\frac{3}{4}$ I multiply the inequality by $24$, then: $4x+3\leq12x-18\\3\leq8x-18\\21\leq8x\\\frac{21}{8}\leq x$
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