Answer
$a=\frac{b+c}{bx-1}$
Work Step by Step
The given equation is
$\Rightarrow x=\frac{a+b+c}{ab}$
Multiply each side by $ab$.
$\Rightarrow ab\cdot x=ab\cdot \frac{a+b+c}{ab}$
Simplify.
$\Rightarrow abx=a+b+c$
Subtract $a$ from each side.
$\Rightarrow abx-a=a+b+c-a$
Simplify.
$\Rightarrow abx-a=b+c$
Use distributive property.
$\Rightarrow a(bx-1)=b+c$
Divide both sides by $bx-1$.
$\Rightarrow \frac{a(bx-1)}{bx-1}=\frac{b+c}{bx-1}$
Simplify.
$\Rightarrow a=\frac{b+c}{bx-1}$
Hence, the rewritten literal equation is $a=\frac{b+c}{bx-1}$.
