Answer
$x=-2, 4$
Work Step by Step
$x-\sqrt {17-4x}-3=0$
$x-\sqrt {17-4x}-3-x+3=0-x+3$
$-\sqrt {17-4x}=-x+3$
$(-\sqrt {17-4x})^2=(-x+3)^2$
$17-4x=(-x*-x+(-x)*3+3*(-x)+3*3)$
$17-4x=x^2-6x+9$
$x^2-2x-8=0$
$x=(-b±\sqrt {b^2-4ac})/2a$
$x=(-(-2)±\sqrt {(-2)^2-4*1*-8})/2*1$
$x=(2±\sqrt {4+32})/2$
$x=(2±\sqrt {36})/2$
$x=(2±6)/2$
$x=(2±6)/2$
$x=(2+6)/2$
$x=8/2$
$x=4$
$x=(2±6)/2$
$x=(2-6)/2$
$x=-4/2$
$x=-2$
