Answer
See below
Work Step by Step
Given: $3x+y=10\\-x+2y=20$
Multiply the second equation by $3$:
$-3x+6y=60$
Then add it to the first equation $7y=70\\
\rightarrow y=10$
Substitute: $3x+10=10\\
\rightarrow 3x=0\\
\rightarrow x=0$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Mixed Review - Page 315: 62
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